Question

A cuboidal tin box open at the top has dimensions 20 cm X 16 cm X 14 cm. What is the total area of metal sheet required to make 10 such boxes in square metres?​

Answer 1

Given :-

• A cuboidal tin box open at the top has dimensions 20 cm × 16 cm × 14 cm.

To find :-

• Total area of metal sheet required to make 10 such boxes in square metres

Solution :-

• Length of cuboidal tin = 20cm
• Breadth of cuboidal tin = 16 cm
• Height of cuboidal tin = 14 cm

As we know that

Total surface area of cuboid

→ 2(lb + bh + lh)

But it is given that cuboidal tin box open at the top.

→ lb + 2(bh + lh)

→ 20 × 16 + 2(16*14 + 20*14)

→ 320 + 2(224 + 280)

→ 320 + 2 × 504

→ 320 + 1008

→ 1328 cm²

Therefore, total surface area of tin is 1328cm²

→ Total area of metal sheet required to make 10boxes

→ 1328 × 10

→ 13280cm²

Hence,

• Required area to make 10 boxes is 13280cm²

Answer 2

174800m^2.

Step-by-step explanation:

area=2(lb)+2(bh)+2(hl).

according to formula,

2(20×16)+2(16×14)+2(14×20)

640+548+560

1748m^2.(for 1 box).

for 10 such bokes,

1748×10=174800m^2.