A cuboidal tin box opened at the top has dimensions 20 cm × 16 cm× 14 cm. What is the total area of metal sheet required to make such a box? Also, find it's volume.
Answers
Hey mate! here you go your answer...
---> The total area of metal sheet required to make 10 such boxes is 13280 sq.cm.
Step-by-step explanation:
Length of box = 20 cm
Breadth of box = 16 cm
Height of box = 14 cm
Lateral surface area of box and one base = 2(l+b)h +lb
= 2(20+16)(14)+(20 \times 16)2(20+16)(14)+(20×16)
=1328 cm^21328cm2
Metal sheet required for 1 box = 1328 sq.cm.
Metal sheet required for 10 boxes = 1328 \times 10 = 13280 cm^21328×10=13280cm2
Hence the total area of metal sheet required to make 10 such boxes is 13280 sq.cm.
Explanation:
Hope it's helpful for you
Answer:
total surface area of cuboidal tin box = 2(lb+bh+hl)-lb
(opened at the top)
=2(20x16+16x14+14x20)- 20x16
=2(320+224+280)- 320
= 2x824-320
= 1648-320
= 1328 cm2
The total area of metal sheet required to make 10 such boxes is 13280 sq.cm. Metal sheet required for 1 box = 1328 sq.cm.
volume of cuboidal tin box= lxbxh
= 20x16x14
= 4480 cm3