A cuboidal tin open at the top has dimensions 20 cm x 16 cm x 14 cm. What is the
total area of a sheet of metal required to make 10 such tins?
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Answer:
Area of cubodial tin = 2(lb+bh+lh)
= 2× {(20×16)+(16×14)+(14×20)
=2× 824
= 1648
therefore , Total area of 10 such tins = 1648×10
16480 tins.
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