A cuboidal tin open at the top has dimensions 20 cm x 16 cm x 14 cm. What is the total area of a sheet of metal required to make 10 such tins.
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Answer:
Step-by-step explanation:
A cuboid has four sides (s) of equal area and two ends (e) of equal area. I'll assume that 20cm = length, 16cm = height and 14cm = width. The area of each side is 20cm x 16cm = 360cm2 and the area of each end is 16cm x 14cm = 224cm2. Since the top is open, then each cuboid has only three sides and two ends; and since there are 10 tins, then the total area is:
(3s + 2e)*10 = (3(360cm2) + 2(224cm2))*10
= (1080cm2 + 448cm2)*10 = (1528cm2)*10
= 15,280 cm2.
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