Question

A cuboidal vessel is 10m long and 8m wide . how high must it be made to hold to 192 cubic metres of a liquid?​

Answer 1

Given -

• Length of Cuboidal vessel = 10m

• Breadth of Cuboidal vessel = 8m

• Volume of Cuboidal vessel = 192m³

To find -

• Height of the Cuboidal vessel.

Solution -

Let the height be considered as h

Volume of cuboid = L × B × H

Where,

L = Length

B = Breadth

H = Height

On substituting the values -

Volume = L × B × H

192 = 10m × 8m × h

192 = 80m × h

h = $\cancel{\dfrac{192}{80}}$

$\longmapsto$ h = 2.4m

$\therefore$ Height of Cuboidal vessel is 2.4m

Verification -

Volume = L × B × H

192m³ = 10m × 8m × 2.4m

192m³ = 192m³

LHS = RHS

Hence,proved

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Answer 2

Answer:

Given :-

• A cuboidal vessel is 10 m long and 8 m wide and it made to hold to 192 m³.

To Find :-

• What is the height of cuboidal vessel.

Formula Used :-

$\boxed{\bold{\small{Volume\: of\: cuboid\: =\: Length\: \times Breadth\: \times Height}}}$

Solution :-

Given :

• Volume = 192 m³
• Length = 10 m
• Breadth = 8 m

According to the question by using the formula we get,

⇒ 10 × 8 × h = 192

⇒ 80 × h = 192

⇒ h = $\dfrac{\cancel{192}}{\cancel{80}}$

➠ h = 2.4 m

$\therefore$ The height of cuboidal vessel is 2.4 m.

Let's Verify :-

↦ 10 × 8 × h = 192

Put h = 2.4

↦ 10 × 8 × 2.4 = 192

↦ 80 × 2.4 = 192

↦ 192 = 192

➥ LHS = RHS

Hence, Verified ✔