Question

A cup contains 250g of water. Find the total positive charge present in the cup of water?

Answer 1

cup = 250 ml H2O
mass of cup of water = 250g
mol wt = 18g
no of moles of H2O = 250/18
=13.888 moles
1 mole = 6.022 * 10 raised to the power 23
no of moles in 1 cup = 13.888 * 6.022 * 10 rtdp 23
8.36 * 10 rtdp 24
total proton in 1 water molecule = 10 

charge on proton = 1.6 * 10 rtdp -19 C

total charge = 10 * 8.36 * 10 rtdp 24 * 1.6 * 10 rtdp -19 C
1.338 * 10 rtdp 7 ( answer)

got it now !
find ur mistake

Answer 2

Answer:

Positive charge present in one cup of water = 1.34×10^7C

Explanation:

Mass of water =250g

Molecular mass of water =18g

Number of molecules in 18g of water =6.02×10^2

Number of moleucles in one cup of water = 250/18 × 6.02×10^23

Each molecule of water contains two hydrogen atoms and one oxygen atom, i.e., 10 electrons and 10 protons.

∴ Total positive charge present in one cup of water

= 250/18 ×6.02×10^23×10×1.6×10^−19 C

= 1.34×10^7C