Question

A cup of coffee at 80 °C is left to cool to 30
°C. If the heat capacity of the cup and coffee
is 2.0 kJ K-1 how much heat is released
during the cooling?
(a) 0.04 kJ
(b) 60 kJ
(c) 100 kJ
(d) 160 kJ​

Answer 1

Δt

=k(

2

t

1

+t

2

−t

0

)

60

80−60

=k(

2

80+60

−30)

3

1

=k(40)

k=

120

1

time

60−50

=

120

1

(

2

60+50

−30)

Time=48secs

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Answer 2

Answer:

$10 kJ$

Explanation:

$C = \frac{Q}{delta-theta}$

$2000 = \frac{Q}{80 - 30}$$Q = 100 000 J$

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