A cupper coil has a resistance of 40Ω at 00C.Find the resistance of this coil at 800C. The temperature coefficient of resistance of coil material is 0.0040per 0C
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Answer:
The resistance at 80°C is 62.8Ω
Explanation:
In the context to the given question we have to find resistance of the coil at 80⁰C
given,
T₁ = 0⁰C.
T₂ = 80⁰C.
R₁ = 40 Ω
R₂ = ?
∝ = 0.0040 °C⁻¹
We know that;
temperature coefficient (∝) =( R₂ -R₁) / R₁ (T₂ -T₁)
∝=( R₂ -R₁) / R₁ (T₂ -T₁)
0.0040 =(R₂-40) / 40 ( 80-0)
0.0040 =(R₂-40) / 3200
(R₂-40) = 3200 x 0.0040
(R₂-40) = 12.8
R₂ = 12.8 +40 = 62.8 Ω
The resistance at 80°C is 62.8 Ω .
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