A curious student created a performance profile of his favourite cricketer as R = − x 5 + 6 x 4 − 30 x 3 + 80 x 2 + 70 x + c , where R is the total cumulative runs scored by the cricketer in x matches. He picked three starting values shown in Table A-5.2 and tried to find the value of c . If he uses Sum Squared Error method, then what will be the value of c ?
NO OF MATCHES 1, 2, 3
TOTAL CUMULATIVE SCORE 120, 285, 361
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Answer:
Answer
the player with less standard deviation i more consistant ,
Mean runs of A =
x
ˉ
A
=47.9.
Mean runs of B =
x
ˉ
B
=41.6
we know,
Mean deviation (A)=
∑
t=1
10
10
fi−
x
ˉ
A
∴ Mean deviation (A)=34.177
Mean deviation (B)=7.727
∴ player B is more consistent.
Step-by-step explanation:
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