Question

A current 0.5is drawn by filament of an electric bulb for 10 minuye . Find the amount ofelectrical change​

Answer 1

Given :

• Current (I) = 0.5 A
• Time (t) = 10 minutes

To find :

• Charge (q)

Solution :

The formula of electric current is given by :

$\boxed{\boxed{ \tt current = \frac{charge}{time} }}$

• I = q/t

First , we will need to change the time from minutes to seconds .

1 min = 60 sec

10 min = 10 × 60 = 600 sec

$\therefore$ The time for which the current flows is 600 s .

$\implies \tt 0.5 = \dfrac{q}{600} \\ \\ \tt \implies 0.5 \times 600 = q \\ \\ \implies\boxed{\tt q = 300}$

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• The fundamental property of matter that experiences electric force , either attractive or repulsive , when placed in an electric field is called charge .
• There are two types of charges - positive and negetive .
• Electric current is the amount of charge that flows through the conductor in unit time .
• Both charge and electric current are scalar quantity .

Answer 2

Answer:

The amount of electric charge that flows through the circuit is 300 C.

Explanation:

Given,

Current (i) drawn by a filament = 0.5 A

Time (t) = 10 minutes = 10* 60 sec = 600 seconds

To find: the amount of electric charge that flows through the circuit.

Solution:

Charge is equal to the product of current and time.

i.e Q = it

here, i = 0.5 A , t = 600 sec

Substituting the values,

Q = 0.5 * 600

or, Q = 300 coulomb

Therefore, The amount of electric charge that flows through the circuit is 300 C.