Question

A current 1.5A flows through a resistor when a potential difference of 6V is applied across its ends. The resistance of the given resistor is

Answer 1

Answer :-

$\implies \boxed{ \sf{ R = 4 \: ohm}} \: \:$

To Find :-

→ Resistance of resistor.

Explanation :-

Given that ;

• Current flows (i) = 1.5 A

• Potential difference (V) = 6 volt

• Resistance (R) = ?

We know that ,

According to ohm's law .

$\implies \boxed{ \sf{ i = \frac{V}{R} }\: } \\ \therefore \\ \\ \implies \sf{ 1.5 = \frac{6}{R} } \\ \\ \implies \sf{ R = \frac{6}{1.5} } \\ \\ \implies \sf{ R = \frac{60}{15} } \\ \\ \implies \boxed{ \sf{ R = 4 \: ohm}} \:$

Hence , required resistance is 4 ohm.

Some other identity :-

$(1) \: \sf{ work = e \: q \: } \\ \\ (2) \sf{ power \: = \: vi \: = \frac{ {v}^{2} }{R} } \: \\ \\ (3) \sf{linear \: charge \: density( \lambda )= \frac{q}{l} } \\ \\ (4) \sf{ current = \frac{charge}{time} }$

Answer 2

$\tt{\huge{\red{Solution \: - }}}$

QUESTION :

A current 1.5A flows through a resistor when a potential difference of 6V is applied across its ends.

The resistance of the given resistor is

SOLUTION :

I = 1.5 A

V = 6 volt.

R = ?

According to ohm's law ,

$\begin{lgathered}\implies \boxed{ \sf{ i = \frac{V}{R} }\: } \\ \therefore \\ \\ \implies \sf{ 1.5 = \frac{6}{R} } \\ \\ \implies \sf{ R = \frac{6}{1.5} } \\ \\ \implies \sf{ R = \frac{60}{15} } \\ \\ \implies \boxed{ \sf{ R = 4 \: ohm}} \:\end{lgathered}$