A current 2A flows in an electric circuit as shown in figure.
The current through branch AB is :
(A) 2A
(B)4/3A
(C)2/3A
(D) 1A
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Answered by
4
option c is right answer
Explanation
From the current division rule:
current in the 1st 3Ω resistor in branch PA
= 2 x 6/9
= 4/3 A
current in the 1st 6Ω resistor in branch PB
= 2 x 3/9
= 2/3 A
Again these current will divide to the second parallel set of resistors,
Hence current in 2nd 3Ω resistor in branch BQ from the branch PA
= 4/3 x 6/9
= 8/9 A
similarly current in 2nd 6Ω resistor in branch AQ from the branch PB
= 2/3 x 3/9
= 2/9 A
Hence current in the branch AB
= 8/9 - 2/9
= 6/9
= 2/3
Hence the current in the branch AB will be 2/3 Amperes.
Answered by
2
Answer:
point c is the correct answer so this is the answer of these question
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