Question

- A current-carrying conductor has 8.0 x 1022 free
electrons per metre length and their mean drift
velocity is 8.0 x 10 ms. If a magnetic field of
0.10 T be applied perpendicular to the conductor, then
calculate (i) current in the conductor, ii) force on an
electron and (iii) force imposed per metre length of
the conductor.
-​

Answer 1

Answer:

The average speed of ‘electrons in copper’ is 625 m/s.

Solution:

The given data’s are

Number of electrons per cc in copper  = density of charge carriers

Current I = 1 A

Cross section Area .

The average speed of the electrons is the ‘drift velocity’ of the electrons in a sample. Drift velocity is the ‘average velocity’ attained by charge carriers in a material when electric current is passed. The formula for drift velocity is

Here, I is the current passed in the material, n is the density of charge carriers in the material, q is the magnitude of charge and A is the cross section area of the material exposed to electric field.

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Explanation:

Answer 2

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