Question

A current carrying loop in the form of a right angle isosceles
triangle ABC is placed in a uniform magnetic field acting
along AB. If the magnetic force on the arm BC is F, what is
the force on the arm AC?
(a) - √2 F ⃗
(b) -F ⃗
(c) F ⃗
(d) √2 F ⃗

Answer 1

Answer:

Force along AB is zero as magnetic field is along AB.

The net force on a current carrying loop is always zero.

F

net

=F on AB→+F on BC→+F

Hence on AC,

⟹0=0+F+ (F on AC)

Hence , F on AC is −F