Question

a current carrying rod 2 ampere of length 2.5 cm of weight 200 gram is suspended in uniform magnetic field what is the magnetic field​

Answer 1

Mass of wire (m) = 200 grams or 0.2 kg

length (L) = 1.5 m

Current (I) = 2 A

Acceleration due to gravity (g) = 9.8 m/s^2

The weight of the wire will be balanced by the magnetic force acting in the opposite direction.

Let the magnetic field be B.

mg = ILB

B = 0.653 T

The value of uniform magnetic field is 0.653 T.

Answer 2

Answer:

0.653 is the answers the question