Question

A current carrying thin wire AB is shown in the
figure. Value of magnetic field at point 'P due to
the wire is
Kr-
ЭР
(1) apr (sin 0, – sin0,1
2
(2) de
sine, + sin 0,]
(3) [cos 02 - cos 0,1
4U
(4) 2 (cos0, + cos 02]
ZTE
un af moanotic field in
Cyclotron used to​

Answer 1

Answer:

Option (2)

Explanation:

From the Biot-Savart Law, the general formula derived for the magnetic field at a point due to current carrying thin wire is

$\boxed{B=\frac{\mu_0I}{4\pi r} [\sin\theta_1+\sin\theta_2]}$

The convention is that The angle below perpendicular line is treated negative and angle above perpendicular line is positive.

Here both the angles are on the same side of the perpendicular line

Therefore, if both the angles are negative then the magnetic field will be just in the opposite diretion which does not affect our answer.

Therefore, the right option is option (2)

Hope this is helpful.