a current carrying wire of length one metre is folded in circular form how many circular turns would produce the maximum magnetic moment
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Number of turns for maximum magnetic moment = 1
Explanation:
Given: A current carrying wire of length one metre is folded in circular form.
Find: How many circular turns would produce the maximum magnetic moment.
Solution:
Magnetic moment = iNA
Length of wire = 1 m
Area of circle = πr2
Number of turns = l/2πr
Magnetic moment = iNA = i (l/2πr) πr2 = ilr/2.
So r is taken as maximum by keeping N = 1.
Number of turns for maximum magnetic moment = 1
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Explanation:
Given a current carrying wire of length one metre is folded in circular form how many circular turns would produce the maximum magnetic moment
- Now there is a wire in which current is flowing.
- We need to find the number of circular turns would produce the maximum magnetic moment.
- Let both ends of a wire be p and q. If we fold into a circular shape, ends p and q comes together and let the radius be r
- So this magnetic moment will be equal to μ = n I A where n is the number of turns
- So length L = 2 π r n
- Therefore n = L / 2πR
- Now μ is directly proportional to number of turns n
- So μ α n
- So μ α r^2
- As the magnetic moment increases area decreases.
- So if n = 1 and r = 1
- If n = 2, r = 1/2
- So as the magnetic moment increases area starts decreasing.
- Therefore the maximum magnetic moment is when n = 1, and so area decreases.
Reference link will be
https://brainly.in/question/2318950
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