Question

a current deposited 5 gram of Cu in 1930 minutes from a solution of Cu++ions the strength of current is
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Answer 1

Answer:

0.12 A

Explanation

Given:

Weight of copper deposited, w=5g

Time taken, t= 1930 min = 1930 * 60 s

Formula Used:

From Faraday's 1st Law of Electrolysis, we have

w = Z i t

where, Z = equivalent weight/96500

Solution:

$5=\frac{63.5}{2*96500} * i * 1930 * 60$

i = 0.12A