Physics, asked by shoiab7, 10 months ago

a current I flows through a long straight conductor which is bent into a circular loop of radius R in the middle as shown in the figure

What will be the magnetic feild at point O?​

Attachments:

Answers

Answered by ranapriyanshu92
0

Answer:

As the current is clockwise the magnetic fields will be towards the SOUTH !

Answered by RitaNarine
6

Given:

Current I flows through a long straight conductor which is bent into a circular loop of radius R.

To Find:

The magnetic feild at point O

Solution:

Magnetic field at O due to the straight part of the wire, is given by,

  • Bstraight = \frac{\mu_0}{2\pi R} I
  • Its direction will be upwards, by Right hand Thumb rule.

Magnetic field at O due to the loop of radius R,

  • Bloop = \frac{\mu_0}{4\pi R^{2}} x I x 2πR = \frac{\mu_0}{2R} I
  • Its direction will be downwards.

Therefore net magnetic field at O is given by,

  • B = Bloop + Bstraight
  • B = \frac{\mu_0}{2R} I - \frac{\mu_0}{2\pi R} I , downwards.
  • B = \frac{\mu_0}{2\pi R} I ( π - 1 ) downwards.

The magnetic feild at point O will be B = \frac{\mu_0}{2\pi R} I ( π - 1 ) downwards.

Similar questions