Physics, asked by Anonymous, 2 months ago

a current If 220 V potential difference is applied across an ele of 0.45 A flows in the bulb. What must be the power of the bulb? (A) 99 W (B) 70 W (C) 45 W (D) 22 W

Answers

Answered by watharkarshardool

3

Answer:

(A) 99w

Explanation:

P=V×I (Formula)

V=220V

I=0.45

P=220×0.45

hence, P=99W

Answered by rudrauparkar

1

Explanation:

P = VI

V = 220 V

I = 0.45 A

P = 220 × 0.45

P = 99 W

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