Question

A current in a 3H inductor varies at a rate of 3 A per second find the Voltage across the inductor and energy stored in the magnetic field after 2 seconds

Answer 1

Explanation:

V = - L di/dt

=-3 H 3A /s

= - 9 Volts

Current at the end of 2 sec = 2 * 3 = 6 A

Energy stored in the magnetic field of the inductor = 1/2 L I^2 = 1/2*3* 6² = 54 J