Physics, asked by sonuchuri, 10 months ago

A current in a coil changes from 2.5 A to 0 A in 0.1 s inducing an emf

of 200 V. Calculate the value of self inductance.​

Answers

Answered by pritirakshit63
0

Answer:

of 200 v. calculate the value of self inductance

Answered by abcdefghi76
1

Answer:

ANSWER

Rate of change of current dtdi=0.10.0−2.5

⟹ dtdi=−25 A/s

Induced emf E=200V

Using E=−Ldtdi

∴ 200=−L×(−25)

⟹ L=8H

Similar questions