Question

A current in a coil falls from 2.5a to 2calculate the induced emf in the coil

Answer 1

the current in ac circuit is given by,

I=V/Z

where,

I=current

V=voltage

Z=impedance

and Z is given by Z=under root( R^2 + (Xl^2 - Xc^2 )

where Xl= inductive resistance

Xc= Capacitice resistance

here in this case Xc=0 and Xl= 2 * pi * f *L

where, pi=3.24

f= 50

L=0.2

hence Xl=62.8

and Z=62.8+12 =74.8

and finally current is 250/74.8 =3.34

Hope this helps you ☺️☺️✌️✌️❤️❤️

Answer 2

For the largest mutual inductance, the two loops should be placed coaxially. In this case, flux through a loop due to another loop is the largest; hence, mutual inductance is the largest.

(b) For the smallest mutual inductance, the two loops should be placed such that their axes are perpendicular to each other. In this case, flux through a loop due to another loop is the smallest (