A current in circuit is given by i = 3 + 4 sinwt then the effective value of current is
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Answered by
230
If an instantaneous current is ![\bold{I=I_{dc}+I_{ac}} \bold{I=I_{dc}+I_{ac}}](https://tex.z-dn.net/?f=%5Cbold%7BI%3DI_%7Bdc%7D%2BI_%7Bac%7D%7D+)
= a + bsinωt , where Idc denotes direct current and Iac denotes alternating current.
Then, effective current is given by![\bold{I_{eff}=\sqrt{a^2+\frac{b^2}{2}}} \bold{I_{eff}=\sqrt{a^2+\frac{b^2}{2}}}](https://tex.z-dn.net/?f=%5Cbold%7BI_%7Beff%7D%3D%5Csqrt%7Ba%5E2%2B%5Cfrac%7Bb%5E2%7D%7B2%7D%7D%7D+)
Given, I = 3 + 4sinωt
Compare from above equation
a = 3 and b = 4
Now, Ieff =![\bold{I_{eff}=\sqrt{3^2+\frac{4^2}{2}}} =\sqrt{17}A \bold{I_{eff}=\sqrt{3^2+\frac{4^2}{2}}} =\sqrt{17}A](https://tex.z-dn.net/?f=%5Cbold%7BI_%7Beff%7D%3D%5Csqrt%7B3%5E2%2B%5Cfrac%7B4%5E2%7D%7B2%7D%7D%7D+%3D%5Csqrt%7B17%7DA+)
Hence, answer is √17 A
= a + bsinωt , where Idc denotes direct current and Iac denotes alternating current.
Then, effective current is given by
Given, I = 3 + 4sinωt
Compare from above equation
a = 3 and b = 4
Now, Ieff =
Hence, answer is √17 A
Answered by
15
Answer:
we know that :- I=A+Bsinwt than:-- I=√A²+B²/2
Explanation: so i=3+4sinwt Ans=√ 3²+4²/2=√9+8=√17A
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