Question

A current in flowing in a circuit.
The intensity of current is 10 A.
Calculate the number of electrons that are passed in per second through the circuit.
Given : Change of one electron is 1.6X 10-19C.​

Answer 1

Answer:

6.2*10¹⁹

Explanation:

I=Q/T

I=NE/T

10=n.1.6*10¹⁹/1

n=10/1.6*10¹⁹

n=100*10¹⁹/16

n=6.2*10¹⁹

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