Question

a current is passed through 2 voltameters connected in series. the first container contains xso4(aq.) and second container contains y2so4 (aq.). the relative atomic masses of x and y are in the ratio of 2:1. the ratio of the mass of x liberated to the mass of y liberated is:

Answer 1

Answer: -

Let the current passed be 1 A for 1 s.

Total charge = 1 A x 1 s

= 1 C

Equivalents of charge = $\frac{1C}{96500 C}$

For XSO₄,

X ²⁺ + 2 e → X

2 moles of charge deposits 1 mol of X

$\frac{1}{96500 }$of charge deposits $\frac{1 mol }{2 mol}$ x $\frac{1C}{96500 C}$

Let the atomic mass of X be 2m.

Mass of X deposited = 2m x $\frac{1 }{2 }$ x $\frac{1}{96500}$

For Y₂SO₄,

Y⁺ + e → Y

1 moles of charge deposits 1 mol of Y

$\frac{1C}{96500 C}$ of charge deposits $\frac{1 mol }1 mol}$ x $\frac{1C}{96500 C}$

= $\frac{m}{96500}$

Since the mass of X is 2m, the atomic mass of Y must be m since ratio of atomic masses is 2:1.

Mass of Y deposited = m x $\frac{1 }{1 }$ x $\frac{1}{96500}$

= $\frac{m}{96500}$

Thus the ratio of mass deposited is 1:1 since the same amount of mass is deposited.