Question

A current is passes through two cell in series. The first cell contain XSO4 while second cell contain Y2SO4. The relative active masses of X & Y are 1:2 what is the ratio ? Mass of X liberated : Mass of Y liberated ?​

Answer 1

Answer:

MEDIUM

Share

Study later

ANSWER

According to Faraday's 2nd Law:-

Weight of X deposited(W

1

)∝ Equivalent weight of X[E

1

]

Weight of Y deposited(W

2

)∝ Equivalent weight of y[E

2

]

∴

W

2

W

1

=

E

2

E

1

----------1

∴

W

2

W

1

=

Atomicmass/Valencyofy

Atomicmass/ValencyofX

----------1

For valency of XSO

4

and y

2

SO

4

(i) y

2

SO

4

From Figure-1, we get Valency of SO

4

is 2 and valency of y is 1.

(ii) XSO

4

From Figure-2, both cancel each other.

∴ Valency of X is 2.

From Equation 2,

W

2

W

1

=

1

1

2

2

=

1

1

[∵ Atomic mass ratio of X & y=2:1]

∴

W

2

W

1

=

1

1

.

∴ Mass ratio=1:1.

Explanation:

hope you like the answer