Question

A current loop of area 0.01m2 and carrying a current of 10 a is held perpendicular ti magnetic field of intensity of 0.1 to.the torque in acting loop is

Answer 1

Given:

Area of loop $A = 0.01 m^{2}$

Current $I = 10$ A

Magnetic field intensity $B = 0.1$ T

To Find:

Torque in acting loop is,

 г = $\mu \times B$

 г = $\mu B \sin \theta$

Where $\mu =$ magnetic moment

Here angle between magnetic field and magnetic moment is 0°

 г = $\mu B \sin 0$

 г = 0

Therefore, the torque acting on the loop is zero.