A current of 0.1 a was passed for 965 second through a solution of cu+ solution and 0.03175 g of copper was deposited on the cathode. Calculate the current efficiency for the copper deposition. (cu - 63.5 gm permol)
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Current efficiency = 50%
Explanation:
From Faraday's law of electrolysis, m = It/F * M/z
To calculate the current efficient, we need to calculate the amount of current used. Let it be x .
m = mass of substance liberated at electrode = 0.03175 g
t = time = 965 seconds
M = molecular weight = 63.5
F = Faraday's constant = 96500
z = valency number of ions of the substance
So x = m * F/t * z/M = 0.03175 * 96500/965 * 1/63.5
x = 0.05 amp
Current efficiency = x/I * 100 = 0.05 / 0.1 * 100 = 50%
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