Question

A current of 0-2 A flows through a conductor of resistance 4-5ohm.calculate the potential difference at the ends of conductor

Answer 1

Current =0.2 A.

resistance = 4.5 ohm.

resistance = 4.5 ohm.potential difference = x.

resistance = 4.5 ohm.potential difference = x.we know.

resistance = 4.5 ohm.potential difference = x.we know.V= I x R

resistance = 4.5 ohm.potential difference = x.we know.V= I x Rx=0.2 x 4.5

resistance = 4.5 ohm.potential difference = x.we know.V= I x Rx=0.2 x 4.5potential difference =0.9 v

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Answer 2

✰ Given -

• Current (I) = 0.2 Ampere
• Resistance (R) = 4.5 Ohm

✰ To Find -

• Potential Difference (V) = ?

✰ Solution -

We know Ohm's Formula,

$✓ \: </strong><strong>V</strong><strong> = </strong><strong>I</strong><strong> \times </strong><strong>R</strong><strong>$

Here,

• V = Voltage
• I = Current
• R = Resistance

Placing Values,

$⟶V = 0.2 \times 4.5$

$⟶V = 0.9v$

⛬ Potential Difference (Voltage) is 0.9 Volt