A current of 0.2 ampere flows through a conductor of resistance 4.5 ohm. Calculate the potential difference at the ends of the conductor.
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given
current (I) = 0.2 A
resistance (R) = 4.5 ohm
potential difference (V) = ?
we know that
V = I×R
V = 0.2× 4.5
V = 0.90 v
current (I) = 0.2 A
resistance (R) = 4.5 ohm
potential difference (V) = ?
we know that
V = I×R
V = 0.2× 4.5
V = 0.90 v
Answered by
2
Answer:
given
current (I) = 0.2 A
resistance (R) = 4.5 ohm
potential difference (V) = ?
we know that
V = I×R
V = 0.2× 4.5
V = 0.90 v
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