Physics, asked by Princesspopstar9814, 11 months ago

A current of 0.2 ampere flows through a conductor of resistance 4.5 ohm. Calculate the potential difference at the ends of the conductor.

Answers

Answered by mangatp
19
given

current (I) = 0.2 A
resistance (R) = 4.5 ohm
potential difference (V) = ?

we know that
V = I×R
V = 0.2× 4.5
V = 0.90 v
Answered by realsamir
2

Answer:

given

current (I) = 0.2 A

resistance (R) = 4.5 ohm

potential difference (V) = ?

we know that

V = I×R

V = 0.2× 4.5

V = 0.90 v

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