A current of 0.2 ampere flows through a conductor resistance 4.5_ . calculate the potential difference at the ends of the conductor.
Answers
Answered by
95
R= 4.5 ohm I = 0.2 A
V= I R
V = 0.2×4.5
= 0.9 volt
V= I R
V = 0.2×4.5
= 0.9 volt
Answered by
37
R=4.5ohm
I=0.2A
V=IR
V=0.2×4.5
V=0.9V
I=0.2A
V=IR
V=0.2×4.5
V=0.9V
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