Question

A current of 0.2 ampere is passed through aqueous solution of copper sulphate for one hour calculate the mass of copper deposited at the cathode

Answer 1

Answer:So 4.54 grams are plated deposited at the cathode.

Explanation:

Answer 2

Answer:

x = 6.2176 x 10⁻⁴ Moles

Explanation:

To discover the molar mass of an detail, then you will take the common atomic mass indexed withinside the periodic desk. If you are looking on the detail of copper you'll appearance withinside the periodic desk and discover that it has a median atomic mass of 63.fifty five AMU, so it's the molar mass.

I = 0.2 A

T= 10 min

Q = I x T

Q = 0.2 x 10 x 60

Cuso₄→ Cu²⁺ + So₄²⁻

2F = one mole of Cu

2 x 96500 = one mole of Cu

0.2 x 10 x 60 = x mole of Cu

x= 0.2 x 10 x 60 / 2 x 96500

x = 6.2176 x 10⁻⁴ Moles

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