Question

A current of 0.3 A is passed through a lamp for 2 minutes using a 6-V power supply. The energy
dissipated by this lamp during the 2 minutes is?

Answer 1

Answer:

I hope this will help you

Explanation:

ans is 216 J

Answer 2

Answer:

The energy dissipated by this lamp during the 2 minutes is 216J.

Explanation:

The energy dissipated by the lamp is given as,

$H=I^2Rt$      (1)

Where,

H=energy dissipated the lamp

I=current through the lamp

R=resistance of the lamp

t=time during which the current flows through the lamp

From the question we have,

Current(I)=0.3A

The voltage supplied(V)=6V

Time during which the current flows(t)=2 minutes=2×60 seconds

The resistance of the lamp is given as,

$R=\frac{V}{I}$

$R=\frac{6}{0.3} =20\Omega$      (2)

By substituting the value of I, R, and t in equation (1) we get;

$H=(0.3)^2\times 20\times 2\times 60$

$H=0.09\times 40\times 60=216J$

Hence,  the energy dissipated by this lamp during the 2 minutes is 216J.