Question

A current of 0.30 A flows through a resistance of 500Ω. How much power is
lost in the resistor?

Answer 1

Answer:

P=I^2×R

.30×.30×500

.3600×500

180.0000Watt

Answer 2

Answer:

power lost in conductor = 45W

Explanation:

A current of 0.30 A flows through a resistance of 500Ω.

current flowing through conductor I =0.3A

Resistance of the conductor R= 500Ω

potential drop across conductor = V = IR

= 0.3 × 500

= 150V

power lost in resistor = VI = 150×0.3 = 45W

or power lost in conductor = I^2R

= (0.3)^2 × 500

= 45W

or power lost in conductor = V^2/R

= (150)^2 × 500

= 15×15/5

=15×3

= 45W