Question

A current of 0.5 A exists in a 60-ohm lamp. The applied potential difference is:

Answer 1

Howdy!!


your answer is -----

Given,
Current I = 0.5 A

& resistance R = 60ohm

therefore , by ohm's law

V = IR

=> V = 0.5 × 60

=> V = 30 volt


hence, potential difference is 30volt


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hope it help you

Answer 2

Given - Current and resistance

Find - Potential difference

Solution - Potential difference, current and resistance is related to each other as per the given relation - V = I*R.

Keep the values in formula to find the potential difference.

V = 0.5*60

Performing multiplication

V = 30 Volts

Hence, the applied potential difference is 30 Volts.