Question

A current of 0.5 A exists in a 60-ohm ohmic lamp. The applied potential difference is

Answer 1

Answer:

your answer is -----

Given,

Current I = 0.5 A

& resistance R = 60ohm

therefore , by ohm's law

V = IR

=> V = 0.5 × 60

=> V = 30 volt

hence, potential difference is 30volt