Question

A current of 0.5 A flows through a wire for 6 minutes. How much charge would have passed through the wire? A) 300 C
B) 30 C
C) 180 C
D) 1800 C

Answer 1

Given :

• Current flowing, I = 0.5 A
• Time for which current is flowing, t = 6 min

To find :

• Charge passed through the wire, Q = ?

Formula required :

• Relation between Current (I) , Charge (Q) and time (t)

      I = Q / t

[ Where I is in Ampere, Q is in Coulomb, and t is in seconds ]

• Current is defined as the rate of low of Charge.
• SI unit of Current : Ampere
• SI unit of Charge : Coulomb.

Solution :

Converting time given in min into seconds

→ t = 6 min

→ t = 6 × 60 sec

→ t = 360 sec

Calculating charge through the wire

Using formula

→ I = Q / t

→ 0.5 = Q / 360

→ Q = 0.5 × 360

→ Q = 180 C

therefore,

• Charge passed through the wire is 180 Coulomb.

Hence,

OPTION (C) 180 C is correct.

Answer 2

Answer:

$\tt {\pink{We \: have}}\begin{cases} \sf{\green{Current \: (I)=0.5 \: A}}\\ \sf{\blue{Time \: taken (t)=6\:min = 360 \: sec}}\\ \sf{\orange{Charge (Q)= \: ?}}\\\end{cases}$

$\qquad \tiny \dag \: \underline{\tt Substituting \: the \: given \: values \: in \: given \: below \: formula :}$

$:\implies \sf Current \: (I) = \dfrac{Charge \: (Q)}{Time \: taken \: (t)}$

$:\implies \sf 0.5 = \dfrac{Charge }{360}$

$:\implies \sf Charge = 0.5 \times 360$

$:\implies \underline{\boxed{\textsf{ \textbf{ Charge = 180 Coulomb}}}}$

$\therefore\underline{\textsf{The charge would be passed through a wire is \textbf{180 Coulomb}}}.$

____________________

$\huge\textsf{\textbf{Electric Charge :}}$

• It can be defined as an interinsic property of elementary particles of matter which give rise to electric force between various object.

• The SI unit of charge is coulomb (C).

• It is represented by Q.