Question

A current of 0.5 A is drawn by a filament of an electric bulb for 10
minutes. Find the amount of electric charge that flows through the
Example 12.1
circuit.​

Answer 1

Answer

The amount of charge that flows through the circuit is 300 coulomb

$\bf \large \underline{Given : }$

• The current flowing through circuit is 0.5A
• Amount of times , t = 10mins

$\bf \large \underline{To \ Find : }$

• The amount of charge that flows through the circuit

$\bf \large \underline{Formula \: to \: be \: used : }$

Considering charge Q , current I and time as t we have :

$\bullet \tt\: \: \: I= \dfrac{Q}{t}$

$\bf \large \underline{Solution : }$

We are given ,

I = 0.5 A

t = 10 mins

↦ t = 10× 60s

Now

$\longrightarrow\sf\: \: \: I= \dfrac{Q}{t} \\ \\ \implies \sf Q = It \\ \\ \implies \sf Q = 0.5 \times 10 \times 60s \\ \\ \sf \implies Q = 5 \times 60 \\ \\ \sf \implies Q = 300 \: \: c$

Therefore , required amount of charge is 300 coulomb

Answer 2

Answer:

The amount of electric charge that flows through the circuit is 300 C.

Explanation:

Given,

Current (i) drawn by a filament = 0.5 A

Time (t) = 10 minutes = 10* 60 sec = 600 seconds

To find: the amount of electric charge that flows through the circuit.

Solution:

Charge is equal to the product of current and time.

i.e Q = it

here, i = 0.5 A , t = 600 sec

Substituting the values,

Q = 0.5 * 600

or, Q = 300 coulomb

Therefore, The amount of electric charge that flows through the circuit is 300 C.