A current of 0.5 A is drawn by a filament of an electric bulb for 10 minutes. Find the amount of electric charge that flows through any point of circuit.
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current= charge/time
I=Q/t
here I=0.5 A , t=10 min {10×60=600 seconds}
we need to find Q=?
THEN , Q=It
Q=0.5×600
Q=300 C
HENCE, the amount of charge flows is 300coulomb
I=Q/t
here I=0.5 A , t=10 min {10×60=600 seconds}
we need to find Q=?
THEN , Q=It
Q=0.5×600
Q=300 C
HENCE, the amount of charge flows is 300coulomb
Answered by
0
Answer:
300 COULOMBS is the answer
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