A current of 0.5 A is drawn by filament of an electric bulb for 10 minutes . find the amount of electric that flows through the current.
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Answered by
1
Answer:
Given:
I(current)= 0.5A
t(time)=10min
min change to sec.
10×60=600sec.
Q=?
acc.to ques
I=Q\t
0.5=Q\600
Q=0.5×600
Q=300 coloumb.
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Current = 0.5 A
t =10min
=10X 60=600sec.
current =
quantity of charge moved/time taken
I =Q/t
Q =I /t
=0.5X 600
=300coloumb
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