Question

A current of 0.5 A is drawn by filament of an electric bulb for 10 minutes. find the amount of electric that flows through the circuit.​

Answer 1

I think the question should be.. The amount of electric CHARGE that flow through it...

And it will be

current =0.5A

Time =10min or. 10*60= 600sec

As current (i) = charge(q) / time (t)

0.5 = q /600

q = 0.5 *600

q = 300 coulomb..

Hope it will be helpful...

Thanks

Answer 2

hi mate

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Current = 0.5 A

t = 10 min

=10 X 60 = 600 sec.

current =

quantity of charge moved / time taken

I = Q/t

Q = I /t

= 0.5 X 600

= 300 coloumb

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if like please thank ❤