Question

A current of 0.5 A passes through a conductor in 2 seconds. How many electrons flow through this conductor from one end during this interval of time. ?Charge on each electron is 1.6 × 10^-19 C.

Answer 1

Heya !!




Here,


I = 0.5 A ; T = 2 s


e = 1.6 × 10^-19 c



Using,


I = ne/t , we get



n = It / e = 0.5 × 2 / 1.6 × 10^-19


n = 6.25 × 10^8 electrons.

Answer 2

Aloha user

Question :- a current of 0.5 A passes through a conductor in 2 sec how many electron flow through this conductor from one end during this interval of time ? charge on each electron is 1.6 x 10^-19

ANSWER:-

First of all we can write the given information

=> I= 0.5 A

=> T= 2s

Given ,...the charge on each electron = 1.6 x 10^-19C

We can apply the formula

I=ne/t

That => n=it/ e

So, 0.5 x2/1.6 x10^-19

N= 6.25x10^8

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