Question

a current of 0.5 ampere has been flowing in a circuit for 30 minutes. calculate the number of electrons flowing from one end to the other end of a circuit.​

Answer 1

Answer:

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Answer 2

Answer:

A current of 0.5 ampere has been flowing in a circuit for 30 minutes, the number of electrons flowing from one end to the other end of a circuit is, $2.81\times 10^{21}$ electrons

Explanation:

• Let I be the current flowing through an electrical circuit t be the time of flow and Q be the total charge.  

        We have the expression for the total charge as,

        $Q = It$     ...(1)

        Also, we have another expression for Q as,

        $Q =ne$    ...(2)

       Where n is the number of electrons in the circuit and e is the charge of one electron.

      Equating equations(1) and (2)

      $It = ne$

      or

      $n = \frac{It}{e}$     ...(3)

• From the question,

       $I =0.5A$

       $t = 15 min = 15\times 60 = 900s$

       we know,

       $e = 1.6\times 10^{-19} C$

       Substituting these values into equation (3)

       $n = \frac{0.5 \times 900}{1.6\times 10^{-19}} = 2.81\times 10^{21}$ electrons