Question

A current of 0.5 ampere is drawn by a filament of an electric bulb for 10 minutes. Find the amoint of electrical charge

Answer 1

Answer:

300 C

Explanation:

According to the given question,

I = Current = 0.5 Amp

t = time = 10 min = 10 ×60 = 600 sec

q = charge

And we are asked to find the amount of charge flowing through the bulb.

We know,

• I = q/t

The given formula describe about the electric current.

Electric current -- Rate of charge with respect to time is called electric current.

• q = I × t

Putting the values we get,

• q = 0.5 × 600

• q = 5×60

• q = 300 C

Thus amount of charge flowing through the bulb for 10 min with 0.2 A of current is 300 C.

Answer 2

Answer:

$\fbox {300 C}$

Explanation:

Given :-

Current (I) = 0.5 A

Time (t) = 10 minutes

(t ) in seconds = 10 × 60 = 600 seconds

question :- To find amount of electrical charge (q)

Formula to be used :-

$\fbox {I = q/t }$

q = I.t

▪ q = 0.5 × 600

▪ q = 5 /10 × 600

▪ q = 5 × 60

▪ q = 300

》》 Electric charge is measured in " Columbs"

•°• q = 300 C