A current of 0.5 ampere is drawn by a filament of an electric bulp for 10 minutes. find the amount of electric charge that flows through circuit.
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Answered by
1
We know that I=q/t
q=It
=0.5*10*60
=5*60
=300 C
q=It
=0.5*10*60
=5*60
=300 C
Answered by
2
Answer:
The amount of electric charge that flows through the circuit is 300 C.
Explanation:
Given,
Current (i) drawn by a filament = 0.5 A
Time (t) = 10 minutes = 10* 60 sec = 600 seconds
To find: the amount of electric charge that flows through the circuit.
Solution:
Charge is equal to the product of current and time.
i.e Q = it
here, i = 0.5 A , t = 600 sec
Substituting the values,
Q = 0.5 * 600
or, Q = 300 coulomb
Therefore, The amount of electric charge that flows through the circuit is 300 C.
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