Question

A current of 0.5 ampere is passed through acidulated water for 30 minutes calculate weight of o2 evolved

Answer 1

Answer:0.0746 gram

Explanation:At Anode:

4OH- =2H2O +O2 +4e-

4*96500 C releases O2 =32gram

then,

1C release 32/4*96500

And thus,

Q charge will release O2=32*Q/4*96500

Q=It =1800seconds *0.5 ampere=900C

This implies that, 900C will release O2= 32*900/4*96500=0.0746 gram