Question

a current of 0.5 ampere passes through a conductor in 2seconds. how many electron flow through this conductor during this interval of time
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Answer 1

Answer:

Solution: It is given that a current of 0.5 ampere passes through a conductor in 2 seconds.

Here,

Current, I = 0.5 A.

Time, t = 2 s.

Charge on each electron,

e = 1.6 × 10^-19 C.

As we know that,

Q = ne ..........................(1)

and current, I = Q/t ....(2)

where,

n = number of electrons

e = charge on each electron

t = time taken

By putting the value of Q in equation 2, we get

I = ne/t

Using this formula, we get

I = ne/t

So,

n = It/e

= 0.5 × 2/ 1.6 × 10^-19

= 1/ 1.6 × 10^-19.

= 6.25 × 10^18 electrons.

Therefore, 6.25 × 10^18 electrons flow through this conductor from one end to another end during this interval of time.

Explanation:

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Answer 2

Hey Pretty Stranger!

We know that,

★ I = Q/T

→ Q = I × T

→ Q = 0.5 × 2

→ Q = 1 C

Now,

★ Q = n|e|

→ 1 = n $\sf \: |1.6 \times {10}^{ - 19}|$

→ n = $\sf \: n \: = \dfrac{1}{1.6 \times {10}^{ - 19} }$

→ n = 0.625 × $\sf {10}^{19}$

→ n = 6.25 × $\sf {10}^{18}$