Question

A current of 0.5 ampere passes through a conductor in 2 seconds. How many electrons flow through this conductor from one end to another end during this interval of time? charge on each electron is 1.6 × 10^-19.​

Answer 1

HERE'S YOURS ANSWER:

as we know,

q = it

here's I = 0.5 ampere, t = 2 seconds

q = 0.5 × 2 = 1 c

no of electrons n = q/ e = 1/ 1.6 × 10 ^ -19 = 0.625 × 10 ^ 19 = 6.25 × 10 ^ 18

n= 6.25 × 10 ^ 18

Answer 2

Solution: It is given that a current of 0.5 ampere passes through a conductor in 2 seconds.

Here,

Current, I = 0.5 A.

Time, t = 2 s.

Charge on each electron,

e = 1.6 × 10^-19 C.

As we know that,

Q = ne ..........................(1)

and current, I = Q/t ....(2)

where,

n = number of electrons

e = charge on each electron

t = time taken

By putting the value of Q in equation 2, we get

I = ne/t

Using this formula, we get

I = ne/t

So,

n = It/e

= 0.5 × 2/ 1.6 × 10^-19

= 1/ 1.6 × 10^-19.

= 6.25 × 10^18 electrons.

Therefore, 6.25 × 10^18 electrons flow through this conductor from one end to another end during this interval of time.