Question

A current of 0•5 ampere passing through a silver nitrate solution for 6 minutes deposits 0•2013 gram of silver. Determine the electrochemical equivalent of silver.

Answer 1

Explanation:

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Answer 2

A current of 0•5 ampere passing through a silver nitrate solution for 6 minutes deposits 0•2013 gram of silver. The electrochemical equivalent of silver is 0.0011.

We know, mass of metal deposited is represented by:

m = Z×I×t

where Z = Electrochemical equivalent = (Equivalent weight of metal) ÷ 96500

I = Current passed

t =Total time taken.

From the question, m = 0.2013gm,

I = 0.5 A,

t =  6mins = (6 × 60)s = 360s.

∴ Z = m ÷ (I × t)

⇒ Electrochemical equivalent =  m ÷ (I × t)

⇒ Electro. eqv. =  0.2013 ÷ (0.5 × 360)

∴ Electrochemical equivalent = 0.0011

So, the Electrochemical equivalent of silver is 0.0011